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Oracle Database SQL Sample Questions (Q76-Q81):

NEW QUESTION # 76
Examine the description of the PROMOTIONStable:

You want to display the unique promotion costs in each promotion category.
Which two queries can be used? (Choose two.)
SELECT DISTINCT promo_category || ' has ' || promo_cost AS COSTS FROM

A. promotions ORDER BY 1;
SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1;
B. SELECT promo_category, DISTINCT promo_cost FROM promotions ORDER BY 2;
C.
D. SELECT DISTINCT promo_cost ||' in '|| DISTINCT promo_category FROM promotions
E. ORDER BY 1;
SELECT promo_cost, promo_category FROM promotions ORDER BY 1;

Answer: B,D

NEW QUESTION # 77
View the Exhibit and examine the structure of the PORDUCT_INFORMATION table.
(Choose the best answer.)

PRODUCT_ID column is the primary key.
You create an index using this command:
SQL > CREATE INDEX upper_name_idx
ON product_information(UPPER(product_name));
No other indexes exist on the PRODUCT_INFORMATION table.
Which query would use the UPPER_NAME_IDX index?

A. SELECT product_idFROM product_informationWHERE UPPER(product_name) IN ('LASERPRO', 'CABLE');
B. SELECT UPPER(product_name)FROM product_information;
C. SELECT product_id, UPPER(product_name)FROM product_informationWHERE
UPPER(product_name) = 'LASERPRO' OR list_price > 1000;
D. SELECT UPPER(product_name)FROM product_informationWHERE product_id = 2254;

Answer: A

NEW QUESTION # 78
Examine the data in the INVOICES table:

Examine the data in the CURRENCIES table:
CURRENCY_CODE
-------------
JPY
GPB
CAD
EUR
USD
Which query returns the currencies in CURRENCIES that are not present in INVOICES?

A. SELECT * FROM currencies
MINUS
SELECT * FROM invoices;
B. SELECT currency_ code FROM currencies
INTERSECT
SELECT currency_ code FROM invoices;
C. SELECT currency_ code FROM currencies
MINUS
SELECT currency_ code FROM invoices;
D. SELECT * FROM currencies
WHERE NOT EXISTS (
SELECT NULL FROM invoices WHERE currency_ code = currency_ code);

Answer: C

NEW QUESTION # 79
Which two statements are true regarding the COUNTfunction?

A. COUNT (*)returns the number of rows including duplicate rows and rows containing NULLvalue in any of the columns.
B. A SELECTstatement using the COUNTfunction with a DISTINCTkeyword cannot have a WHERE clause.
C. The COUNTfunction can be used only for CHAR, VARCHAR2, and NUMBERdata types.
D. COUNT(cust_id)returns the number of rows including rows with duplicate customer IDs and NULL value in the CUST_IDcolumn.
E. COUNT(DISTINCT inv_amt)returns the number of rows excluding rows containing duplicates and NULLvalues in the INV_AMTcolumn.

Answer: A,E

NEW QUESTION # 80
View the exhibit and examine the ORDERStable.

The ORDERStable contains data and all orders have been assigned a customer ID. Which statement would add a NOTNULLconstraint to the CUSTOMER_IDcolumn?

A. ALTER TABLE orders
MODIFY customer_id CONSTRAINT orders_cust_nn NOT NULL (customer_id);
B. ALTER TABLE orders
ADD CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);
C. ALTER TABLE orders
ADD customer_id NUMBER(6)CONSTRAINT orders_cust_id_nn NOT NULL;
D. ALTER TABLE orders
MODIFY CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);

Answer: A

NEW QUESTION # 81
......

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